27^(7x-5)=((1)/(81))^(3x-2)

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Solution for 27^(7x-5)=((1)/(81))^(3x-2) equation: 



27^(7x-5)=((1)/(81))^(3x-2)

We move all terms to the left:

27^(7x-5)-(((1)/(81))^(3x-2))=0



Domain of the equation: 81)^(3x-2))!=0

x∈R



We add all the numbers together, and all the variables

27^(7x-5)-((+1/81)^(3x-2))=0

We multiply all the terms by the denominator


(27^(7x-5))*81)^(3x+1-2))-((=0

We add all the numbers together, and all the variables

(27^(7x-5))*81)^(3x-1))-((=0

We add all the numbers together, and all the variables

(27^(7x-5))*81)^(3x=0

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